I had a look thru the Help text and did a Google. I understand the equation to use to construct an inverse RIAA which is
laplace=(1+1.003180*S)*(1+1.000075*S)/((1+1.000318*S)*(1+1.00000318*S))
if one wishes to include the 3.18uS time constant as well.
I have tried the voltage controlled current source but to no avail. I get a variety of error messages.
Does anyone have the answer?
It seems doing things with a laplace equation may be easier and also quicker than an inverse RIAA network - which vary in accuracy.
AndyN
Using Laplace equations for inverse RIAA
Re: Using Laplace equations for inverse RIAA
Sorry, I just stumbled across this, and I don't see that it's ever been answered.andyn wrote:I had a look thru the Help text and did a Google. I understand the equation to use to construct an inverse RIAA which is
laplace=(1+1.003180*S)*(1+1.000075*S)/((1+1.000318*S)*(1+1.00000318*S))
if one wishes to include the 3.18uS time constant as well.
I have tried the voltage controlled current source but to no avail. I get a variety of error messages.
Does anyone have the answer?
It seems doing things with a laplace equation may be easier and also quicker than an inverse RIAA network - which vary in accuracy.
AndyN
Use a voltage-dependent voltage source (e or e2). Set the value to:
Laplace=(((s*T0+1)*(s*T2+1))/((s*T1+1)*(s*T3+1))). Then add Spice directives:
.param T0=3180us
.param T1=318us
.param T2=75us
.param T3=3.18us
Seems to work for me.
JL